good one

E) (-2)^-n = -2^-n 
n = 0 
(-2)^-0 = -2^-0 
1 = -1 
n = 1 
(-2)^-1 = -2^-1 
-0.5 = -0.5 
n = 1 is a solution, so this answer is incorrect 
(D) (-2)^n = -2^n 
n = 0 
(-2)^0 = -2^0 
1 = -1 
n = 1 
(-2)^1 = -2^1 
-2 = -2 
n = 1 is a solution, so this answer is incorrect 
(C) 2^n = (-2)^-n 
n = 0 
2^0 = (-2)^-0 
1 = 1 
n = 0 is a solution, so this answer is incorrect 
(B) 2^-n = (-2)^n 
n = 0 
2^-0 = (-2)^0 
1 = 1 
n = 0 is a solution, so this answer is incorrect 
(A) -2^n = (-2)^-n 
n = 0 
-2^0 = (-2)^-0 
-1 = 1 
n = 1 
-2^1 = (-2)^-1 
-2 = -0.5